Length of an aluminum wire is 100 cm, what will be the increase in its length when its temperature is
increased to 50°C from 30°C? Coefficient of linear expansion for aluminum is 26×10-6/°C.
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Answered by
24
this question is based on thermal linear expansion .
use formula,
L = L°( 1 + a∆T )
where L is final length of wire
L° is initial length of wire .
a is coefficient of thermal expansion .
∆T is temperature difference .
now ,
L = 100{1 + (50-30)×26× 10^-6}
= 100 × { 1 + 20 × 26 × 10^-6}
= 100{ 1 + 520× 10^-6}
= 100{ 1 + 0.000520 )
= 100 × 1.000520
= 100.0520 cm
hence increase in length = L - L°
= 100.0520 - 100 = 0.052 cm
use formula,
L = L°( 1 + a∆T )
where L is final length of wire
L° is initial length of wire .
a is coefficient of thermal expansion .
∆T is temperature difference .
now ,
L = 100{1 + (50-30)×26× 10^-6}
= 100 × { 1 + 20 × 26 × 10^-6}
= 100{ 1 + 520× 10^-6}
= 100{ 1 + 0.000520 )
= 100 × 1.000520
= 100.0520 cm
hence increase in length = L - L°
= 100.0520 - 100 = 0.052 cm
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