Question

Length of an iron rod at 27°C is 10m
(a = 11 x 10-6 /°C). To decrease the
length of the rod by 1.1 mm, temperature
of the rod should be decreased to​

Answer 1

Explanation:

Δl=αl

o

ΔT

⇒ΔT=

αl

o

Δl

=

1.1×10

−6

×10

1.1×10

−3

=10

T=27

∘

−10

∘

=17

∘

C

Ans.(C)