Question

Length of base is 8 cm and its perpendicular is 6 CM find its perimeter

Answer 1

Answer: 24cm

Step-by-step explanation: Pythagoras' theorem

hypotenous squar = height squar + base squar

so the hypotenous=root(64+36)

 = 10

perimeter = 10+6+8 cm

=24cm

Answer 2

$\Large{\underline{\underline{\bf{Solution :}}}}$

As, Base(B) = 8 cm

Perpendicular(P) = 6cm

We can find the hypotenuse(H) by using phythagorean theorm.

We know that,

$\Large{\implies{\boxed{\boxed{\sf{(H)^2 = (P)^2 + (B)^2}}}}} \\ \\ \sf{→(H)^2 = (6)^2 + (8)^2} \\ \\ \sf{→(H)^2 = 36 + 64} \\ \\ \sf{→(H)^2 = 100} \\ \\ \sf{→(H)^2 = (10)^2} \\ \\ \sf{→H = 10 \: cm}$

$\rule{150}{2}$

Now, we have to find perimeter of the triangle.

We know the formula to find the perimeter of tge triangle.

$\large{\implies{\boxed{\boxed{\sf{Perimeter = Sum \: of \: all \: sides}}}}}$

$\sf{→Perimeter = 6 + 8 + 10} \\ \\ \sf{→Perimeter = 14 + 10} \\ \\ \sf{→Perimeter = 24 \: cm}$

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