Length of chord PQ is 12cm. Radius of a circle is 10cm. Find the distance
of chord PQ from the centre.
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Let AB=12 cm be the chord of the circle with radius AO=10 cm
Draw OP⊥AB Join OA
AP=
2
1
AB=
2
1
×12=6cm
In △APO,∠P=90
∘
∴AO
2
=AP
2
+OP
2
⇒10
2
=6
2
+OP
2
⇒OP
2
=100−36
⇒OP
2
=64
⇒OP=8cm
Hence the distance of the chord from the circle is 8 cm.
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