Question

length of diagonal AC and BD of a rhombus are 12 CM 16 m respectively find the length of each side

Answer 1

In a Rhombus ABCD
Diagonals intersect at O
AC=12cm
​BD=16cm

half of AC=AO
half of 12cm=A0
​AO=6cm

half of BD=OD
half of 16cm=OD
OD=8cm

AD=side of rhombus ABCD
side2=AO​2 + OD2 (pytha. theorum)
side2=62 + 82
side2=36 + 64
side2=100
side2=102

Answer 2

In rhombus 12cm is d1
16 cm is d2
so half of the both diagonal are 6 cm and 8 cm
(AB ) ^2 = (AO)^2+(BO)^2(Pythagoras. trip.)

let Ab =x
x^2 = (6)^2+(8)^2
x^2=100
$\sqrt{100}$
x= 10
the all sides of rhombus are equal = 10cm