Question

length of diagonal of a rectangle whose length 48 and breadth 40 cm

Answer 1

Length of rectangle = 48 cm

Breadth of rectangle = 40 cm

length of diagonal of a rectangle = √ (length² + breadth²)

=> diagonal = √ ( 48²+40²)

=> diagonal = √ ( 2304 + 1600 )

=> diagonal = √ 3904 = 62.48 cm



hope this helps

Answer 2

Heya mate,
Here is your answer,

length of the rectangle = BC = AD = 48cm
breadth of the rectangle = AB = CD = 40cm

length of the diagonal = ?

In ∆ABC,
height = AB = 40cm
base = BC = 48cm
hypotenuses = AC = ?

Since all the angles of a rectangle are 90°,
∆ABC is a right angled triangle, So

AC² = AB² + AC²
=> AC² = (40)² + (48)²
=> AC² = 1600 + 2304
=> AC² = 3904
=> AC = √3904 = 62.48 cm

Hence the length of the digonal is 62.48cm

Hope this helps

if you have further doubt or want any help ask me. i would like to help.

Thank you

#Sneha
Brainly benefactor