Question

Length of diagonal of square 13root2 find it’s perimeter

Answer 1

Answer:

Diagonal of square =√2a

13√2=√2a

13=a

Perimeter of square=4*s

Perimeter=4*13=52

Answer 2

$\huge \tt{Answer}$

Given:-

• Diagonal of square 13_/2

Solution:-

$diagonal \: AC= \sqrt{a²+a} \\ from \: pythagoras \: theorem$

$so \: AC=a \sqrt{2}$

$13 \sqrt{2} =a \sqrt{2}$

$a=13$

Length of side is 13cm

Perimeter of square=4×Side

=13×4

=52 cm²