length of diagonal square field is 7√2 find perimeter
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Answer:
28 units.
Step-by-step explanation:
Consider a Square ABCD, where AD is the diagonal.
Let 'S' be the side of the square.
Given,
AD = 7√2 units
we know that by using Pythagoras theorem,
AD² = AC² + CD²
=> (7√2)² = S² + S²
=> 2S² = 98
=> S² = 49
=> S = 7 units.
Perimeter of Square = 4 * Side = 4 * 7 = 28 units.
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