length of diagonals of a rhombus are 20 cm and 21 cm.
find length of its sides and perimeter
Answers
Answered by
2
Answer:AB^2=AD^2+OB^2
=10^2+10.5^2
=100+110.25
=210.25
AB=14.5 IS THE SIDE OF THE RHOMBUS
PRIMETER=4S
=4(14.5)
=58 CM
Step-by-step explanation:
Answered by
1
As the diagonals of rhombus bisects each other by 90°
Then
By Pythagoras theorem,
(20/2)²+(21/2)²=side²
10²+(21/2)²=side²
100+441/4 =side²
(400+441)/4=side²
841/4 =side²
√{841/4} =side
29/2 =side
Then
Perimeter =4*side
Perimeter =4*29/2
Perimeter =2*29
Perimeter =58cm
Step-by-step explanation:
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