Question

Length of e.coli dna is 1.36mm ,calculate number of base pairs in e.coli

Answer 1

The distance between two base pairs in a nucleotide sequence is .34nm = .34*10-9m. 

I m = 1000mm

.34*10-9m = .34*10-6 mm

Length of E coli DNA = 1.36 mm

Hence the number of base pairs = 1.36 mm/34*10-6 mm

The answer for this is 4*106 basepairs.

Answer 2

Distance between two consecutive base pair = 0.34 nm

Total length of given DNA = 1.36mm  

∴ total no. of base pair =  1.36mm /0.34nm

⇒ 4 × 10⁶ Base pair.