Length of equal side of a triangle is 4m less from the third side.If the perimeter of triangle is 55m.Find the dimensions of the tiangle.
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let the third side be x m
so , other two equal sides =(x-4)m
and,the perimeter of the triangle is 55m
A/q
x+(x-4)+(x-4)=55
x+x-4+x-4=55
3x-8=55
3x=63
x=21
Hence, the sides are 21m,17m,17m.
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Answer:
Given,
equal side of a triangle is 4 less than the third side
let side A and B =x
therefore,third side =4+x
now,sum of all sides =perimetre
threfore,x+x+4+x=55
3x+4=55
3x=55-4
x=51÷3
x=17m
and third side =x+4
17+4=21m
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