Question

Length of hypotenuse of the right angle triangle whose side is 45m and 18m

Answer 1

h=√(45×45) +(18×18)
=answer

Answer 2

Apply Pythagoras theorm buddy :)

${h} = \sqrt{ {b}^{2} + {p}^{2} }$
here h = hypotenuse , b= base, p= perpendicular

now
${h} = \sqrt{ {45}^{2} + {18}^{2} }$
solving ,
$h = \sqrt{2025 + 324}$
$h = \sqrt{2349}$

so h = 48.46