length of one division of main scale of a vernier calliper is 0.1cm .find the value of vernier constant
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Answer:
MSD=0.01cm
L.C =0.02 cm
least count
no of divisions on vernier scale =n
length of vernier scale =m
value of one vernier scale division
1VsD=
n
m
L.C =1 MSD - IVSD
0.02=0.1−
n
m
n⋅
m
=0.1−0.02
only one option satisfies above
n=10m=0.8 cm
Explanation:
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