Question

Length of one of the diagonals of a rectangle whose sides are 6 cm and 8 cm is

Answer 1

Step-by-step explanation:

Step-by-step explanation:

the formula of the diagonal of a rectangle is: d= the square root of wight squared plus length squared (sorry i can't insert the mathematical symbols)

6 and 8 squared and added gives= 36+64=100

the square root of 100 is 10 therefore the diagonal is 10 cms long

Answer 2

Given:-

• Sides of rectangle are 6cm and 8cm.

To Find:-

• The length of diagonals of the rectangle .

Formula Used:-

We will use " Pythagoras Theorem " , which is stated as "In a right angled ∆ the sum of squares of base and perpendicular is equal to the square of hypotenuse .

$\large{\underline{\boxed{\red{\tt{(hypontenuse)^2=(base)^2+(perpendicular)^2 }}}}}$

Answer:-

We know that in a rectangle all angles are equal to 90°.

so between two adjacent sides the angle between them would be equal to 90 degree.if we join the two sides with the diagonal then it will form a right angle triangle.

[ For figure refer to attachment : ]

Let AC be the diagonal and AB and BC be the two adjacent sides.

So , in ∆ABC ,

⇒ AC² = AB² + BC² .

⇒ AC² = (6cm)² + (8cm)² .

⇒ AC² = 36cm² + 64cm².

⇒ AC² = 100cm²

⇒ AC = √[100cm²].

⇒ AC = ± 10 cm .

Since we know that sides can't be negative . Hence AC = 10cm .

Hence the measure of diagonal is 10 centimetre.