Length of one of the equal sides of an isosceles triangle is 4 cm . If its base is 2 cm then what is its area ?
Answers
Answered by
14
Answer:
4 cm^2
Step-by-step explanation:
Area of isosceles️ = (1/2 × b × h) or (bh/2)
where base b=2cm
height h=4cm
=1/2 × b × h
=1/2 × 2 × 4
=8/2
=4cm^2
OR
=bh/2
=2×4/2
=8/2
=4cm^2
Answered by
3
Answer:
=4cm^2
Step-by-step explanation:
Area of isosceles️ = (1/2 × b × h) or (bh/2)
where base b=2cm
height h=4cm
=1/2 × b × h
=1/2 × 2 × 4
=8/2
=4cm^2
OR
=bh/2
=2×4/2
=8/2
=4cm^2
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