Question

length of one of the equal sides of an isosceles triangle is 4 cm. If its be is 2 cm then what is its area?FIND USING HERON's formula​

Answer 1

Answer:

$\sqrt{15}$ cm² (or) 3.873 cm²

Step-by-step explanation:

given base , b = 2cm and one of the equal sides is 4cm

=> a = 4cm, b=2cm, c = 4cm ( as isosceles)

by heron's formula ,

Area of a triangle , A = √(s (s-a) (s-b) (s-c) )

where s is given by , s = (a+b+c)/2

now

s = (4+2+4)/2 = 10/2 = 5

so, the Area A = √(5 (5-4) (5-2) (5-4) ) cm²

                        = √(5 (1) (3) (1) ) = $\sqrt{15}$ cm²

                        = √5 * √3 cm²

                        = 2.236 * 1.732 cm²

                        = 3.873 cm²