Question

length of one of the equal sides of an isosceles triangle is 4 cm. If its be is 2 cm then what is its area?
a. √15cm2
b. √13cm2
c. √12cm2
d. √14cm2

Answer 1

take 12 divided 2 = 6cm

take 14 divided by 2 is 7

Answer 2

Given: Isosceles traingle

Equal side (a) = 4 cm

side b = 2 cm

To find: area

S = a + b + c

2

S = a + a + b (Isosceles traingle)

2

S = 4 + 4 + 2

2

S = 5 cm

Area of traingle=

$\sqrt{s (s - a)(s - b)(s - c)}$

=

$\sqrt{5(5 - 4)(5 - 4)(5 - 2)}$

=

$\sqrt{5 \times 1 \times 1 \times 3}$

=

$\sqrt{15} {cm}^{2}$

So, Area of traingle is √15 cm²