Length of one side of a square floor is 8m How many square stones of side 2 m can be fixed on the floor
Answers
Answered by
1
8×8=64 (l×b)
b= 8 because it is a square so all sides are equal
64÷2= 32
so 32 stones can fit in that square floor.
Step-by-step explanation:
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Answered by
5
Answer:
16 square stones required
Step-by-step explanation:
Dimension of the floor = 8*8 msquare =64 msquare
Dimension of one stone = 2*2 square = 4 msquare
so, number of stones can be fixed on the floor
= 64/4 = 16 square stones required
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