Math, asked by subhashkhatik8923, 8 months ago

Length of one side of a square floor is 8m How many square stones of side 2 m can be fixed on the floor​

Answers

Answered by kaycee2537
1

8×8=64 (l×b)

b= 8 because it is a square so all sides are equal

64÷2= 32

so 32 stones can fit in that square floor.

Step-by-step explanation:

hope it helps ;)

pls mark brainliest

Answered by mamtasinha3105
5

Answer:

16 square stones required

Step-by-step explanation:

Dimension of the floor = 8*8 msquare =64 msquare

Dimension of one stone = 2*2 square = 4 msquare

so, number of stones can be fixed on the floor

= 64/4 = 16 square stones required

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