Question

Length of one side of an equilateral triangle is 8 cm .find its area and length of the altitude

Answer 1

Answer:

4$\sqrt3$

Step-by-step explanation:

according to heron's formula, area of the triangle having sides a,b,c units is

A = $\sqrt s(s-a) (s-b) (s-c)$

where

s = a+b+c by 2

for the given triangle

a=b=c= 8cm

s = 8+8+8 by 2

s = 12cm

A = $\sqrt 12(12-8) (12-8) (12-8)$

A = root 3 × 4 × 4cube

4 × 4$\sqrt3$

16$\sqrt3$

AREA OF THE TRIANGLE = 1/2 × BASE × ALTITUDE = 16$\sqrt3$

1/2 × 8 × altitude = 16$\sqrt3$

ALTITUDE = 16$\sqrt3$ BY 4

4$\sqrt3$

THIS IS THE ANSWER

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