Question

length of p=5,s=3,q=4,t=2. find the area​

Answer 1

Answer:

=5 y

1

=1

x

2

=−3 y

2

=−5

m:n=1:1

By mid-point formula

(3,y)=(

2

5+1

,

2

−3−5

)

3=

2

6

y=

2

−8

y=−4.

please make brain list answer please

20 is answer ok

Answer 2

P(x

1

,y

1

),Q(x

2

,y

2

),R(x

3

,y

3

) are vertices of a triangle

ar(△PQR)=

2

1

[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]

=

2

1

[−5(−5−5)−4(5−7)+4(7+5)]

=

2

1

[50+8+48]

=

2

1

[50+56]

=

2

1

×106

=53sq.unit