Question

length of potentiometer wire is 2m and resistance is 4 ohm. a current flows trough it by cell of emf 2 volt. find the position of the balance point if a cell of emf 1.08 is connected.

Answer 1

current =2÷4=0.5A
so EMF=1.08 = i× resistance per unit length × l
=0.5×2×l

implies l=1.08 m =108 cm...