Question

Length of rectangle = 8cm . Each diagonal measures 10cm . Find perimeter of the rectangle?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer :-

PERIMETER = 28 cm

Explaination :-

★ Given :-

• Length of the rectangle = 8cm

• Diagonal = 10cm

★ To find :-

• The BREADTH of the RECTANGLE

• The perimeter of the RECTANGLE

★ Solution :-

•→ First we need to find the Breadth.

•→ Breadth can be found through the Pythagorus theorem.

Refer the attachment for the diagram.

→ Hypotenuse : 10cm

→ Height : x

→ Base : 8cm

=> (Hypotenuse)²=( Base) ² + ( Height )²

$= > ( {10})^{2} = ({8})^{2} + ( {x})^{2}$

$= > {10}^{2} = {8}^{2} + {x}^{2}$

$= > 100 = 64 + {x}^{2}$

$= > {x}^{2} = 100 - 64$

$= > {x}^{2} = 36$

$= > x = \sqrt{36}$

$= > x = 6$

$\large{\green{\boxed{\green{\boxed{\red{\textsf{Breadth = 6 cm }}}}}}}$

$\textbf{\large{PERIMETER}}$

=> 2 ( L + B )

=> 2 ( 8 + 6 )

=> 16 + 12

=> 28

$\large{\green{\boxed{\green{\boxed{\red{\textsf{PERIMETER = 28 cm }}}}}}}$

$\therefore$ The PERIMETER of the RECTANGLE = 28 cm