Question

length of rectangle exceed it's breadth by 12 CM. If the perimeter of the rectangle is 64 CM. find the length and breadth of the rectangle ​

Answer 1

Answer:

let b=x

and l=x+12cm

and p=64

Step-by-step explanation:

so

x+x+12=64

2x+12=64

2x=64-12

x=52/2

x=26

b=26

l=26+12

pls mark as branliest

Answer 2

Answer :-

• Breadth of the rectangle is 10cm
• length of the rectangle = 22cm.

Step by step explanation:

To find :-

• Length and breadth is the rectangle.

Solution:

Let the breadth of the rectangle be x

& Let the length of the rectangle be (x + 12).

We know,

$\bigstar \boxed{\bf { Perimeter = 2(L + B)}}$

Where,

• Length = (x + 12)
• Breadth = x
• Perimeter = 64cm

Therefore,

$\longrightarrow \bf 2(x + 12 + x) = 64$

ᅠᅠ

$\longrightarrow \bf 2x + 24+ 2x = 64$

ᅠᅠ

$\longrightarrow \bf 4x + 24 = 64$

ᅠᅠ

$\longrightarrow \bf 4x = 64 - 24$

ᅠᅠ

$\longrightarrow \bf 4x = 40$

ᅠᅠ

$\longrightarrow \bf x = \cancel{ \dfrac{40}{4} }$

ᅠᅠ

$\longrightarrow \bf x = 10$

ᅠᅠ

Therefore, Breadth of the rectangle is 10cm and length of the rectangle = 22cm.