length of rectangle exceed it's breadth by 7cm if the perimeter of the rectangle is 45cm find the length and breadth
Answers
Answered by
2
Step-by-step explanation:
let breadth = x
then length =7+x
perimeter of a rectangle =
2(l+b)
= 2×{x+(7+x)}=45
= 2× {x+x+7}=45
2(2x+7)=45
=4x + 14 =45
=4x =45-14
=x=31÷4
x=7.75
length = 7.75 + 7= 14.75cm
breadth = 7.75cm
Answered by
0
Given,
length of the rectangle exceeds its breadth by 7cm
perimeter = 45cm
To find,
Length and breadth
Solution,
Let the breadth be x
length = x + 7
Perimeter of a rectangle = 2(l + b)
45 = 2 (x + x + 7)
45 = 2 (2x + 7)
45 = 4x + 14
45 - 14 = 4x
31/4 = x
7.75 = x
So, the breadth of the rectangle is 7.75cm
Length = x + 7
= 7.75 + 7
= 14.75
Therefore, the length of the rectangle is 14.75 cm and its breadth is 7.75cm
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