Math, asked by abdulravoofgdk, 10 months ago

length of rectangle exceed it's breadth by 7cm if the perimeter of the rectangle is 45cm find the length and breadth​

Answers

Answered by sanghvikavya193
2

Step-by-step explanation:

let breadth = x

then length =7+x

perimeter of a rectangle =

2(l+b)

= 2×{x+(7+x)}=45

= 2× {x+x+7}=45

2(2x+7)=45

=4x + 14 =45

=4x =45-14

=x=31÷4

x=7.75

length = 7.75 + 7= 14.75cm

breadth = 7.75cm

Answered by HrishikeshSangha
0

Given,

length of the rectangle exceeds its breadth by 7cm

perimeter = 45cm

To find,

Length and breadth

Solution,

Let the breadth be x

length = x + 7

Perimeter of a rectangle = 2(l + b)

45 = 2 (x + x + 7)

45 = 2 (2x + 7)

45 = 4x + 14

45 - 14 = 4x

31/4 = x

7.75 = x

So, the breadth of the rectangle is 7.75cm

Length = x + 7

= 7.75 + 7

= 14.75

Therefore, the length of the rectangle is 14.75 cm and its breadth is 7.75cm

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