Question

length of rectangle exceed its breadth is 5 metres if the perimeter of rectangle is 66 metres find its length and breadth​

Answer 1

✬ Length = 19 m ✬

✬ Breadth = 14 m ✬

Step-by-step explanation:

Given:

• Length of a rectangle exceeds its breadth by 5 metres.
• Perimeter of rectangle is 66 metres.

To Find:

• What is the measure of length and breadth of rectangle ?

Solution: Let the breadth of rectangle be x m. Therefore,

➟ Length = 5 m more than x

➟ Length = (x + 5)

As we know that

★ Perimeter of Rectangle = 2(Length + Breadth) ★

A/q

• Perimeter is 66 m.

$\implies{\rm }$ 66 = 2(x + 5 + x)

$\implies{\rm }$ 66 = 2(2x + 5)

$\implies{\rm }$ 66 = 4x + 10

$\implies{\rm }$ 66 – 10 = 4x

$\implies{\rm }$ 56 = 4x

$\implies{\rm }$ 56/4 = x

$\implies{\rm }$ 14 = x

So,

➙ Breadth is x = 14 m

➙ Length is 14 + 5 = 19 m

___________________

★ Verification ★

➭ 66 = 2(19 + 14)

➭ 66 = 2(33)

➭ 66 = 66

$\large\boxed{\texttt{Verified}}$

Answer 2

Let the Breadth be x.

It is given that the length is 5 metres more than the breadth.

So, We Can Write Length as x + 5.

Now,

☢ Given :-

• Breadth = x metres.

• Length = x+5 metres.

• Perimeter = 66 metres.

☢ To Find :-

• Length and Breadth.

☢ Solution :-

➨2(Length + Breadth) = 66m.

Put the values.

➨2(x + x + 5) = 66.

➨2(2x + 5) = 66.

➨4x + 10 = 66.

➨4x = 66 - 10

➨4x = 56

➨x = 14.

So,

✔ Breadth = x = 14m.

✔ Length = x+5 = 19m.