Question

Length of rectangle is 2 cm more than twice its breadth. If the perimeter of the recte
(a
28 cm, find its length and breadth.​

Answer 1

Let the -

• breadth of rectangle be x

Length of rectangle is 2 cm more than twice it's breadth.

Breadth of rectangle = 2x + 2

Perimeter of rectangle = 2(length + breadth

Also given that perimeter of rectangle is 28 cm.

Substitute the known values in above formula

→ 28 = 2(2x + 2 + x)

→ 28 = 2(3x + 2)

→ 28 = 6x + 4

→ 6x = 28 - 4

→ 6x = 24

→ x = 4

•°• Breadth of rectangle = 4 cm

And

•°• Length of rectangle = 2(4) + 2

→ 8 + 2

→ 10 cm

Verification :-

From above calculations length of rectangle = 10 cm and breadth of rectangle = 4 cm

And we have given that perimeter of rectangle is 28 cm

→ 28 = 2(10 + 4)

→ 28 = 2(14)

→ 28 = 28

Answer 2

$\large \underline{ \underline{ \sf \: Solution : \: \: \: }}$

Given ,

$\to$Perimeter of rectangle = 28 cm

Let ,

$\to$Breadth of rectangle = x

$\to$So , length = 2 + 2x

We know that ,

$\large \fbox{ \fbox{ \sf Perimeter = 2(length + breadth)}}$

$\implies \sf 28 = 2(2 + 2x + x) \\ \\ \implies \sf \frac{28}{2} = 2 + 3x \\ \\\implies \sf 14 - 2 = 3x \\ \\\implies \sf 3x = 12 \\ \\\implies \sf x = \frac{12}{3} \\ \\\implies \sf x = 4$

$\therefore$Breadth = 4 cm & length = 10 cm