length of rectangle is 5 less than twice its breadth if its perimeter is 110, then find the area of rectangle by any algebraic method.
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Hiii Friend,
Let the Breadth of a rectangle be X.
Then the Length of rectangle = 2X -5
Perimeter of rectangle = 110
2(L+B) = 110
2(2X - 5 +X) = 110
(2X -5+X) = 110/2
3X - 5 = 55
3X = 55-5
3X = 50
X = 50/3 = 16.66 cm
Breadth of rectangle = X = 16.66 cm
And,
Length of rectangle = 2X - 5 = 2 × 16.66 -5 = 33.32-5 = 28.32 cm
Therefore,
Area of rectangle = L × B = 28.32 × 16.66 = 471.81 cm².
HOPE IT WILL HELP YOU..... :-)
Let the Breadth of a rectangle be X.
Then the Length of rectangle = 2X -5
Perimeter of rectangle = 110
2(L+B) = 110
2(2X - 5 +X) = 110
(2X -5+X) = 110/2
3X - 5 = 55
3X = 55-5
3X = 50
X = 50/3 = 16.66 cm
Breadth of rectangle = X = 16.66 cm
And,
Length of rectangle = 2X - 5 = 2 × 16.66 -5 = 33.32-5 = 28.32 cm
Therefore,
Area of rectangle = L × B = 28.32 × 16.66 = 471.81 cm².
HOPE IT WILL HELP YOU..... :-)
DAJ2003:
thanks for your answer saniya....
Srry but ur answers is incorrect
3x - 5 = 55 it becomes 3x = 60 ( - 5) changes to +5
step is wrong 3x - 5 =55 , 3x = 55+5 , 3x =60, x =20 , but written 3x = 55-5 , so wrong answer, correct answer is 700 sq units
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