Question

length of rectangle is 7 more than is breadth and its diagonal is 1 more than its lenght.find the length,breadth,area,perimeter of rectangle​

Answer 1

Answer:

Let the breadth be b and thus length will be b+7

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle=

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l 2

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l 2 +b

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l 2 +b 2

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l 2 +b 2

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l 2 +b 2

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l 2 +b 2

Let the breadth be b and thus length will be b+7The perimeter of rectangle =34 cm⇒2(l+b)=34⇒2(b+7+b)=34⇒4b+14=34⇒4b=20⇒b=5∴l=12now diagonal of rectangle= l 2 +b 2 =13cm