Length of rectangle is 8m less than twice it's breath. If the perimeter of the perimeter of the rectangle is 56 m,find its length AND breadth.
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Answered by
6
Let the breadth be = x
Length = 2x-8
So, perimeter = (2x-8)+(2x-8)+x+x = 56
6x-16 = 56
6x = 56+16
6x = 72
x = 72/6
x = 12
Length = 2(12) - 8 = 24 - 8 = 16m
Breadth = 12m
Length = 2x-8
So, perimeter = (2x-8)+(2x-8)+x+x = 56
6x-16 = 56
6x = 56+16
6x = 72
x = 72/6
x = 12
Length = 2(12) - 8 = 24 - 8 = 16m
Breadth = 12m
Answered by
3
Let the breadth of the rectangle =x m
Twice the breadth =2x m
Therefore,it's rectangle =(2x-8) m
Perimeter of the rectangle =2(length+breadth)
Thus,perimeter =2(2x-8+x) m
=2(3x-8) m
=(6x-16) m
The perimeter of rectangle is 56 m
Therefore,6x-16=56
6x=56+16
6x=72
X=72/6
X=12
Breadth of the rectangle =12 m
Length of the rectangle =2×12-8=16 m
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