Question

length of rectangle is trhirce of it’s breadth perimeter 24 cm then find dimensions ​

Answer 1

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Length of Rectangle is three times of it's breadth.

• Perimeter of Rectangle is = 24 cm.

$\;\;\underline{\textbf{\textsf{ To Find :-}}}$

• Dimensions of the rectangle perimeter

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

Let the Breadth of Rectangle be x cm

Given that,

Length of Rectangle is three times of it's breadth.

Then,

• Length of Rectangle will be = 3x cm

⠀⠀⠀⠀⠀⠀

We know that,

$\star\;{\boxed{\sf{\purple{Perimeter_{\;(Rectangle)} = 2(l + b)}}}}$

$\underline{\:\textsf{ Now, put the given values :}}$

$\dashrightarrow \sf 2(3x + x) = 24$

$\dashrightarrow \sf 2(4x) = 24$

$\dashrightarrow \sf 8x = 24$

$\dashrightarrow \sf x = \cancel{ \dfrac{24}{8}}$

$\dashrightarrow {\boxed{\frak{\purple{x = 3}}}}\;$

$\;\;\underline{\textbf{\textsf{ Hence-}}}$

• Length of Rectangle will be

= 3 × x

= 9 cm

• Breadth of Rectangle = 3 cm

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Answer 2

Answer:

Let length of rectangle=lcm

breadth of rectangle= bcm

Given length is 3 times its breadth

i.e. l= 3×b

Perimeter of the rectangle= 120 cm

i.e.2×( l+ b)=120

2×(3×b+ b)=120

2×(4×b)=120

8×b=120

b= 15 cm