Question

length of rectangle shape park exceeds its breadth by 17 meters the park perimeter of 178 M find dimensions of park

Answer 1

The breadth of the park  =  36  meters  and Length of the park   = 36  +  17 =  53  meters.

Step-by-step explanation:

Let the breadth of the park be   =  x  meters

Then the length of the park  =  x + 17  meters

• Perimeter of the park  

=  2 ( l e n g t h + b r e a d t h ) = 2 ( x + 17 + x )  meters

=  2 ( 2 x + 17 ) meters

But it is given that the perimeter of the rectangle is   178 meters

• Breadth of the park

2 ( 2 x + 17 )  =  178

4 x + 34  =  178

4 x  =  144

x  =  144 /  4  =  36

Therefore the breadth of the park  =  36  meters

• Length of the park   = 36  +  17 =  53  meters.

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Answer 2

✬ Length = 53 m ✬

✬ Breadth = 36 m ✬

Step-by-step explanation:

Given:

• Length of rectangular park exceeds breadth by 17 m.
• Perimeter of rectangular park is 178 m.

To Find:

• What is the length and breadth of the park ?

Solution: Let the breadth of rectangular park be x meters. Therefore,

➯ Length of park = 17 m more than breadth.

➯ Length = (x + 17) m

Now, as we know that

★ Perimeter of Rectangle = 2( Length + Breadth ) ★

But according to the question

• Perimeter = 178 m

$\implies{\rm }$ 178 = 2 ( x + 17 + x )

$\implies{\rm }$ 178 = 2 ( 2x + 17 )

$\implies{\rm }$ 178 = 4x + 34

$\implies{\rm }$ 178 – 34 = 4x

$\implies{\rm }$ 144 = 4x

$\implies{\rm }$ 144/4 = x

$\implies{\rm }$ 36 m = x

Hence,

➟ Breadth of park = x = 36 m

➟ Length of park= x + 17= 36+17 = 53 m