Math, asked by vibhor8173, 6 months ago

length of rectangular ground is 3 more then it's breadth. perimeter of ground is 76. find the dimensions​

Answers

Answered by MoodyCloud
39

Dimensions :-

  • Length is 20.5 .
  • Breadth is 17.5 .

Step-by-step explanation:

Given:-

  • Perimeter of ground is 76.

To find:-

  • Dimensions of ground.

Solution:-

Let, Breadth of rectangular ground be x.

And, Length of rectangular ground be x + 3 [We take length be x + 3 because it is given that length is 3 more than Breadth]

We know,

Perimeter of rectangle = 2(l + b)

Where,

  • l is length and b is breadth

Put the values:

 \longrightarrow 76 = 2 × (x + 3 + x)

 \longrightarrow 76 = 2x + 6 + 2x

 \longrightarrow 76 = 4x + 6

 \longrightarrow 76 - 6 = 4x

 \longrightarrow 70 = 4x

 \longrightarrow x = 70/4

 \longrightarrow x = 17.5

Verification:-

 \longrightarrow 76 = 2×(x + 3 + x)

  • Put x = 17.5

 \longrightarrow 76 = 2×(17.5 + 3 + 17.5)

 \longrightarrow 76 = 2×(20.5 + 17.5)

 \longrightarrow 76 = 41 + 35

 \longrightarrow 76 = 76

 \boxed{\sf Hence \: Verified.}

Dimensions are:

We take

Breadth be x . So, Breadth of rectangular ground is 17.5 .

Length be x + 3 = 17.5 + 3 = 20.5. Thus, Length of rectangular ground is 20.5 .

Answered by shaktisrivastava1234
24

 \Huge \rm \fbox{Correct Question}

 \sf{Length  \: of \:  rectangular  \: ground  \: is \:  3 \:  more \:  then}

 \sf{its  \: breadth.If  \: perimeter  \: of  \: ground  \: is \:  76cm, find}

 \sf{its  \: dimensions.}

  \Huge \rm \fbox{Answer}

 \Large \bf{Given:}

 \sf\implies{Breadth  \: of \:  rectangle= {\bf{x}} \: cm}

 \sf\implies{Length  \: of  \: rectangle=3 +  {\bf{x}} cm}

 \sf\implies{Perimeter  \: of  \: rectangle=76 {cm} }

 \Large \bf{To  \: find:}

 \leadsto \sf{Dimension \:  of  \: rectangle. }

 \Large \bf{Formula  \: required:}

 \fbox{Perimeter of rectangle=2(length+breadth)}

 \Large \bf{According \:  to  \: Question:}

 \sf \mapsto{Perimeter \:  of  \: rectangle=2(length+breadth)}

 \sf \mapsto{76 {cm} =2(3  + {\bf{x}}+ \bf{x})}

\sf \mapsto{  \frac{76}{2} =3 + 2 {\bf{x}}}

 \sf \mapsto{ 38 =3 + 2 {\bf{x}}}

 \sf \mapsto{ {38} - {3}  = 2{\bf{x}}}

 \sf \mapsto{   35 = 2{\bf{x}}}

\sf \mapsto{   \frac{35}{2} = {\bf{x}}}

\sf \mapsto{  17.5 = {\bf{x}}}

 \sf{ \longrightarrow{Breadth  \: of  \: rectangle=17.5cm}}

\sf{ \longrightarrow{Length  \: of  \: rectangle=17.5cm + 3 = 20.5cm}}

 \Large \bf{Verification:}

\sf \mapsto{Perimeter  \: of  \: rectangle=2(length+breadth)}

\sf \mapsto{76cm=2(20.5+17.5)}

 \sf \mapsto{76cm=2 \times 38.0}

  \sf \mapsto{76cm=76cm}

 \fbox{L.H.S=R.H.S}

____________________________________

Similar questions