Length of resonance tube is 150 cm minimum level of liquid in resonance condition for wave having wavelength it is m is
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The possible resonance for wave will be 3.
Explanation:
Correct statement:
Length of resonance tube is 150 cm how many resonance are possible for a wave having frequency 400 hertz and speed of sound is 320 metre per second ?
Solution:
- Frequency = 400 hertz
- Sound velocity = 320 m/s
- Length of tube = 150 cm
We need to calculate the wavelength
Using formula of wavelength
λ = v / f
Put the value into the formula
λ = 320 / 400 = 0.8 m = 80 cm
We need to calculate the number of resonance
Using formula of number of resonance
- For one loop
L= λ / 2
L= 80 / 2 =40 cm
- For second loop
L = λ / 2 = 2 x 80 / 2 = 80 cm
- For third loop
L = λ / 2 = 3 x 80 / 2 = 120 cm
- For fourth loop
L = λ / 2 = 120 x 4 / 2 = 160 cm
Here, the length of the tube is 150 cm so neglect of the fourth loop.
Hence, The possible resonance for wave will be 3.
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