Length of tangent from a point P to circle x2 + y2 = 6 is twice the length of the tangent from P to the circle
x2 + y2 + 3x + 3y = 0, then locus of the point Pis:
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Length of Tangent from a Point (a,b) to a Circle x
2
+y
2
+2gx+2fy+c=0
is L=
a
2
+b
2
+2ga+2fb+c
So, According to Question
f
2
+g
2
−6
=2
f
2
+g
2
+3f+3g
⇒f
2
+g
2
−6=4(f
2
+g
2
+3f+3g)
⇒3f
2
+3g
2
+12f+12g+6=0
⇒f
2
+g
2
+4f+4g+2=0
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