Length of the chord of a circle is equal to its radius, find the angle subtended by this chord at
the centre of the circle.
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the angle subtended by this chord at
the centre of the circle will be equal to 60° because it is forming an equilateral triangle
the centre of the circle will be equal to 60° because it is forming an equilateral triangle
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Answered by
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O is the centre of the circle.
AB chord = radius OA
OA = OB ( Radii of same circle )
Therefore ,
In ∆OAB ,
OA = OB = AB
OAB is an equilateral triangle.
<A = <B = <O = 60°
Angle subtended by the chord at the
center = 60°
••••
AB chord = radius OA
OA = OB ( Radii of same circle )
Therefore ,
In ∆OAB ,
OA = OB = AB
OAB is an equilateral triangle.
<A = <B = <O = 60°
Angle subtended by the chord at the
center = 60°
••••
Attachments:
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