length of the classroom is 2 times its height and the breadth is 1. 1/2 and half time is its height the cost of the fight watching wall at the rate of 1.63 per metre square is rupees 17 9.20 find the cost of the tearing the floor @ rupees 6.75 per metre square
Answers
Answered by
21
Let height be x
Length=2x
Breadth =1 1x/2=3x/2
Area of 4 walls of room=179.20÷1.60=112m^2
2 (l+b)×h=112
2 (2x+3x/2)×x=112
2×7x^2/2=112
x^2=16
x=4
So height=4m
Length=8m
Breadth=6m
For tiling the floor we will find the area
Area=l×b=8×6=48m^2
Cost of tiling the floor =48×12.75=Rs.612
Required answer is Rs.612
Hope it helps! Mark as brainliest! !
Length=2x
Breadth =1 1x/2=3x/2
Area of 4 walls of room=179.20÷1.60=112m^2
2 (l+b)×h=112
2 (2x+3x/2)×x=112
2×7x^2/2=112
x^2=16
x=4
So height=4m
Length=8m
Breadth=6m
For tiling the floor we will find the area
Area=l×b=8×6=48m^2
Cost of tiling the floor =48×12.75=Rs.612
Required answer is Rs.612
Hope it helps! Mark as brainliest! !
Similar questions