Question

Length of the diagonal AC and BD of a rhombous are 6 and 8 respectively. Find the length of each side of the rhombus

Answer 1

Continued

3^2 + 4^2 = BC^2

9+16= BC^2

25=BC^2

5=BC

Since one side of rhombus is 5 cm and all sides of a rhombus are equal

AB=5cm

BC=5cm

CD=5cm

DA=5cm

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Answer 2

Answer:

Hi Friend, I hope my answer helps you.

AC = 6 units

BD = 8 units

AC⊥BD

Let the point of intersection of AC and BD be O.

AO = OC = 3 units

BO = OD = 4 units

In Δ AOD,

AO = 3 units

DO = 4 units

∠AOD = 90°

According to the pythagoras theorem,

Hy^2 = P ^2 + B^2

∴(AD)^2 = 3^2 +4^2

  AD      = √9+16

             = √25

             = 5 units

∴Length of each side of the rhombus = 5 units.

ANSWER : 5 units.