length of the diagonal of a rhombus 6cm and 8 cm. find the length of the each side of a rhombus
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5 cm each side of rhombus will be the answer
diagonal divides equal parts
3, 4 cm
and diagonal bisect each other at 90°
by Pythagoras theroem
side²=3²+4²=9+16=25
side=√25=5 cm will be the answer
diagonal divides equal parts
3, 4 cm
and diagonal bisect each other at 90°
by Pythagoras theroem
side²=3²+4²=9+16=25
side=√25=5 cm will be the answer
govindgorai198p8yigs:
how explain it
let me..... explain
in rhombus there are four right angle traingle
each side 5 cm , perimeter = 20 cm
then take perpendicular of any tringle half of 1st diagonal i.e. 4. then take base half of 2nd daigonal i.e. 3 now with formula of paythagorous theorm find h then h = side
its so simple
mene solve kar diya he
thik h isne pucha how to maine bataa diayaa
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