Question

Length of the diagonals of a rhombus are 16.5 cm and 14.2cm, find its area.​

Answer 1

★ Given :

• Length of the diagonals of a rhombus are 16.5 cm and 14.2cm.

★ To find :

• Area of Rhombus

★ Solution :

Area of Rhombus = 1/2 × D₁ × D₂

➤ 1/2 × 16.5 × 14.2

➤ 2/234.3

➤ 117.15cm²

Area of Rhombus is 117.15cm²

More to Know :

• Area Of Rectangle = L × B

• Area of Square = (Side)²

• Area of Rhombus = 1/2 × D₁ × D₂

• Area of Parralegram = Base × Height

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Answer 2

Answer :

Area of Rhombus is 117.5cm².

Solution :

Given :

• Length of the diagonals of a rhombus are 16.5 cm and 14.2 cm.

To Find :

• Area of the Rhombus.

$\red\bigstar\:\boxed{\sf Area_{Rhombus} = \frac{1}{2} \times d_1 \times d_2 }$

Let,

• d1 = 16.5 cm.
• d2 = 14.2 cm.

Applying the formula here,

$\sf \leadsto Area_{Rhombus} = \frac{1}{2} \times 16.5 \times 14.2$

$\sf \implies Area_{Rhombus} = \frac{1}{2} \times 234.5$

$\sf \leadsto Area_{Rhombus} = \underline{\boxed{\pink {\sf 117.5cm^2}}}$

Hence,

Area of Rhombus is 117.5cm².

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More to know :

$\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}$

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