length of the each side of a rhombus is 25 m length of the one of its diagonal is 14 metres find the area of Rhombus
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A=pq÷2
a=p²+q²÷2
Solving forA
A=1÷2p √4a²﹣p²=
1÷2·14·√4·25²﹣14²=336m²
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area of rhombus =1/2×d1×d2x
d2=14^2+x^2=25^2
x^2=25^2-14^2
x^2=625-196
x= sguare root of 429
x=20.7
Khushideswal111:
207/2×14
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