Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD=17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
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ANSWER WILL BE 662m^2
Step-by-step explanation:
BC = 48 m, CD = 17 m, DA = 40m
Given & length of fence of Trapezium = 120 m
Now,
Perimeter of trapezium = Length of fence
AB + BC + CD + DA = 120
AB+ 48 + 17+ 40 = 120
AB+ 105 =120
AB 120 105
Since AB _ BC,
AB is the height of the trapezium
Now,
Area of trapezium = (a + b) x h
Putting h = Height = AB = 15m
a = length of Parallel side = 40
& b Length of other Parallel side = 48 cm
Area = 1/2(40+48)×15
= 1/2×88+15
= 44 x 15
= 660 m²
Area of field = 660 m²
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