length of the fence of a trapezium shaped field pqrs is 120m. if qr= 48m, rs= 17 m and ps = 40m, find the area of this field. side pq is perpendicular to the parallel sides ps and qr. find its area.
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Answer:
We have,
perimeter of trapezium=120m
=pq+qr+rs+ps=120m
=pq+48m+17m+40m=120m
=pq+105m=120m
=pq=120m-105m
=pq=15m
Since ,pq is the perpendicular, we have,
Area of trapezium:
=(1/2)×(ps+qr)×pq
=(1/2)×(40m+48m)×15m
=(1/2)×88m×15m
=660m²
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