Question

length of the fence of trapezium shaped field ABCD is 120m. if BC =48m,CD =17mand AD= 40m,find the area of this field. side AB is petpendicular to the parallel sides AD andBC​

Answer 1

Answer:

:area of trapezium 1/2x hieght(sum of parameter)

:area of trapezium 1/2x hieght(sum of parameter) a=1/2x 40(40 + 48)

:area of trapezium 1/2x hieght(sum of parameter) a=1/2x 40(40 + 48) a = 20 x 88

:area of trapezium 1/2x hieght(sum of parameter) a=1/2x 40(40 + 48) a = 20 x 88 area of trapezium = 1760

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Answer 2

Answer:

Area of the field = 660m²

Step-by-step explanation:

Length of the fence = Perimeter

AB+BC+CD+AD = 120m

AB+48m+17m+40m = 120m

AB+105m = 120m

AB = 120m-105m

AB = 15m

Now,Area of Trapezium (ABCD) = 1/2*(AD+BC)*AB

= 1/2*(40m+48m)*15m

= 1/2*88m*15m

= 660m²