Math, asked by goudrameshb, 5 months ago

length of the field is 5 m more than its breadth if perimeter is 30m the area is​

Answers

Answered by Anonymous
0

\huge\color{pink}{\bf{Answer}}

Let the Breadth be x

Length=x+5

Given perimeter=30cm

Perimeter=2×(l+b)

=>2×[(x+5)+x]=30

=>2x+10+2x=30

=>4x+10=30

=>4x=30-10

=>4x=20

=>x=20/4

=>x=5

Breadth=5m

Length=x+5=5+5=10m

Area=l×b

=>10×5=50m²

❥Hope it helps you....

Answered by vaibhavrahalkar
0

Answer:

Here , length and breadth are mentioned, the field is regtangle.

l \:  =  \: 5 + b

Perimeter of regtangle = 2 (l + b)

thus,

30 = 2(l + b) \\ 15 = l + b \\

We know that, L = 5 + b

15 = 5 + b + b \\ 10 =  2b \\ b = 5

Now , b = 5

l = 5 + b \\  = 5 + 5 = 10

Here , l = 10 and b = 5

Area of regtangle = l x b

= 10 x 5

= 50

Therefore, the area of triangle is 50m².

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