Question

length of the given field is 5m more than its breatdth. If perimeter is 30m then the area is?

Answer 1

Answer:

Let be breadth=x

A.T.Q

Length=x+5

Perimeter=2(L+b)

. 30=2(x+5+x)

. 30=2(2x+5)

. 15=2x+5

. 15-5=2x

. 10/2=x

. x=5

b=5

L=10

Area=LXb

. =10X5

. =50m

.

Answer 2

Question:-

length of the given field is 5m more than its breatdth. If perimeter is 30m then the area is?

Answer:-

• The area of rectangle is 50 m².

Given:-

• Length = x +5 m
• Breadth = x m
• Perimeter = 30 m

To find:-

• Area of rectangle

Solution:-

$\boxed{ \large{perimeter = 2(length + breadth}}$

$\implies \:2 (x + 5 + x) = 30 \\ \\ \implies \:2x + 5 = \frac{30}{2} \\ \\ \implies \:2x = 15 - 5 \\ \\\implies \:x = \frac{10}{2} \\ \\ \implies \:x = 5\: m$

• The breadth is 5 m.
• The length is (x+5) = (5+5)= 10 m

$\boxed{ \large{area = length \times breadth}}$

$\implies \: area = 5 \times 10 \\ \\ \implies \: area =50 \: {m}^{2}$

Hence,

The area of rectangle is 50 m².