Math, asked by ruchika679, 2 months ago


Length of
the lotus rectum of the conic
25 [(x-2)^2 + (y-3)^2]=(3x-4y+7)^2


Answers

Answered by lalitnit
0

Answer:

Length of the lotus rectum of the conic

25 [(x-2)^2 + (y-3)^2]=(3x-4y+7)^2

The solution is attached.

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