Question

Length of
the lotus rectum of the conic
25 [(x-2)^2 + (y-3)^2]=(3x-4y+7)^2

Answer 1

Answer:

Length of the lotus rectum of the conic

25 [(x-2)^2 + (y-3)^2]=(3x-4y+7)^2

The solution is attached.