Math, asked by tyagiharshit2003, 7 months ago

Length of the perpendicular from the centre of the ellipse 27x^{2} +9yx^{2} =243 on a tangent drawn to it which makes equal intercepts on the coordinates axes is?

Answers

Answered by preetkaur9066
0

Answer:

Given ellipse is 16x

2

+9y

2

=144

9

x

2

+

16

y

2

=1

So tangent to the ellipse at any point

θ

is given by,

3

xcosθ

+

4

ysinθ

=1

∴x−intercept =

cosθ

3

and y−intercept =

sinθ

4

Now given both intercepts are equal ⇒

cosθ

3

=

sinθ

4

⇒tanθ=

3

4

∴sinθ=

5

4

and cosθ=

5

3

therefore required equation of the tangent is, x+y=5

Hope it helps you

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