Length of the perpendicular from the centre of the ellipse on a tangent drawn to it which makes equal intercepts on the coordinates axes is?
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Answer:
Given ellipse is 16x
2
+9y
2
=144
⇒
9
x
2
+
16
y
2
=1
So tangent to the ellipse at any point
′
θ
′
is given by,
3
xcosθ
+
4
ysinθ
=1
∴x−intercept =
cosθ
3
and y−intercept =
sinθ
4
Now given both intercepts are equal ⇒
cosθ
3
=
sinθ
4
⇒tanθ=
3
4
∴sinθ=
5
4
and cosθ=
5
3
therefore required equation of the tangent is, x+y=5
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