Question

length of the rectangle exceeds it's breadth by 4m if the perimeter of the rectangle is 84m find its length breadth​

Answer 1

Answer:

2(l+b)= 84

l = 4+x

b = x

2(x+x+4)= 84

4x + 8 = 84

Step-by-step explanation:

now you can solve it by yourself thank u

Answer 2

Given :

• Length of a rectangle exceeds its breadth by 4 m. Perimeter of the rectangle is 84 m.

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To Find :

• Find the breadth of rectangle.

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Solution :

~ Formula Used :

$\large{\color{cyan}{\bigstar}} \: \: {\underline{\boxed{\red{\pmb{\sf{ Perimeter{\small_{(Rectangle) }} = 2 \bigg\lgroup Length + Breadth \bigg\rgroup }}}}}}$

Here :

• ➳ Length = y + 4
• ➳ Breadth = y

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Calculating the Value of y :

${\longmapsto{\qquad{\sf{ Perimeter{\small_{(Rectangle) }} = 2 \bigg\lgroup Length + Breadth \bigg\rgroup }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 84 = 2 2 \bigg\lgroup (y + 4) + y \bigg\rgroup }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 84 = 2 \times 2y + 4 }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 84 = 4y + 8 }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 84 - 8 = 4y }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ 76 = 4y }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ \cancel\dfrac{76}{4} = y }}}} \\ \\ \ {\qquad{\textsf{ Value of y = {\blue{\sf{ 19 }}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Calculating the Dimensions :

$\\ \large{\orange{\dashrightarrow{\underline{\underline{\green{\sf{ Length = y + 4 = 19 + 4 = 23 }}}}}}}$

$\large{\orange{\dashrightarrow{\underline{\underline{\green{\sf{ Breadth = y = 19 }}}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

Therefore :

❝ Length of the rectangle is 21 m and the breadth is 19 m. ❞

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