Length of the rectangle is 5 cm more than its breadth .area is 300 sq.cm. find length and breadth
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Answer:
let breadth be bcm
and length be lcm
ATQ
l =b+5-----eqn1
area given=300 sq CM
b( b+5) =300
b*2 +5 b= of rectangle is 20 cm300
b*2+20b -15b=300
b*2+20b -15b-300=0
b(b+20) -15(b+20) =0
(b+20) (b-15) =0
b=-20 , b=15
not possible
Step-by-step explanation:
when b= 15
then l= b+5
l =15+5
l=20cm
hence length of rectangle is 20 cm
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