Question

length of the rectangle is twice of its breadth if the perimeter is 56 find its length and breadth please answer Please ​

Answer 1

❖ Given :-

• Length of Rectangle is twice of the Breadth

❖ To Find :-

• Length and breadth of Rectangle

❖ Solution :-

Let Breadth of Rectangle be 'x'

Let Length of Rectangle be '2x'

Perimeter of Rectangle = 66cm

A.T.Q.

$\longrightarrow{Perimeter = 2(L+B)}$

$\longrightarrow{66 = 2(2x+x)}$

$\longrightarrow{66 = 2(3x)}$

$\longrightarrow{66 = 6x}$

$\longrightarrow\dfrac{66}{6}={x}$

$\longrightarrow{x\:=\:11}$

Length = 2x = 2×11 = 22cm

breadth = x = 11cm

❖ Verification :-

Length = 22cm

Breadth = 11cm

Perimeter = 2(L+B)

= 2(22+11)

= 2×33

= 66

❖ More to know :-

• Rectangle is a 2D shape in geometry
• It's opposite sides are equal
• It's opposite sides are parallel
• Angles in a Rectangle are always 90°

Answer 2

Correct Question:-

• Length of the rectangle is twice of its breadth if the perimeter is 66 find its length and breadth.

⠀

Given:-

• Length of the rectangle is twice of its breadth.
• Perimeter of rectangle is 56 cm.

⠀

To find:-

• Length and breadth of the rectangle.

⠀

Solution:-

• Let the breadth of rectangle be x.
• Let the length of rectangle be 2x.

⠀

★Formula used:-

$\star{\boxed{\sf{\orange{Perimeter\: of\: rectangle = 2(l + b)}}}}$

⠀

$\tt:\longmapsto{66 = 2(l + b)}$

⠀

$\tt:\longmapsto{66 = 2(2x + x)}$

⠀

$\tt:\longmapsto{66 = 4x + 2x}$

⠀

$\tt:\longmapsto{66 = 6x}$

⠀

$\tt:\longmapsto{x = \dfrac{66}{6}}$

⠀

$\tt:\longmapsto{\boxed{\red{x = 11\: cm}}}$

⠀

Hence,

• Breadth = 11 cm
• Length = 2x = 22 cm

⠀

Diagram:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 22cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 11cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$